Question

The equation of line passing through (2,3)&with slope 5 is

Answer 1

Answer:

eq of line y= mx+c

y=5x+c

putting value of x and y

3=10+c

c=-7

eq of line y= 5x-7

Answer 2

EXPLANATION.

Equation of line,

Passing through points = (2,3).

Slope = 5.

m = slope of line.

As we know that,

Equation of line,

⇒ (y - y₁) = m(x - x₁).

Put the values in equation, we get.

⇒ (y - 3) = 5(x - 2).

⇒ y - 3 = 5x - 10.

⇒  - 5x - 3 + 10 = 0.

⇒ y - 5x + 7 = 0.

                                                                                                                   

MORE INFORMATION.

Angle of intersection of two curves.

If two curves y = f₁(x) and y = f₂(x) intersect at a point p, then the angle between their tangents at p is,

tanФ = ± (dy/dx)₁ - (dy/dx)₂/1 + (dy/dx)₁(dy/dx)₂.

The other angle of intersection will be (180° - Ф).

If two curves intersects orthogonally that is at right angle then,

(dy/dx)₁.(dy/dx)₂ = -1.