The equation of motion of a particle executing shm is a+16π^2=0. In this equation, a is the linear acceleration in m/s^2 of the particle at a represented by y=0.08[3πt+π/4]metre. Find the time period
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Hello dear,
There's lot of useless data here to confuse you.
◆ Answer-
T = 0.67 s
◆ Solution-
Comparing the eqn. y = 0.08sin[3πt+π/4] with standard form y = Asin[ωt+φ], we can write-
A = 0.08 m
ω = 3π
φ = π/4
Time period in SHM is calculated by-
T = 2π/ω
T = 2π / 3π
T = 2/3 s
T = 0.67 s
Therefore, time period in given SHM is 0.67 m.
Hope it helps...
There's lot of useless data here to confuse you.
◆ Answer-
T = 0.67 s
◆ Solution-
Comparing the eqn. y = 0.08sin[3πt+π/4] with standard form y = Asin[ωt+φ], we can write-
A = 0.08 m
ω = 3π
φ = π/4
Time period in SHM is calculated by-
T = 2π/ω
T = 2π / 3π
T = 2/3 s
T = 0.67 s
Therefore, time period in given SHM is 0.67 m.
Hope it helps...
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