the equation of motion of a particle is s=3t^2-18t. find the time when the particle comes to rest
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Answer:
The particle is at rest at 2 times, at
t = 0 and t = 6, but we don't consider the time t = 0, as it's the time when the particle starts it's journey, obviously it will be at rest in that moment.
Explanation:
As the particle comes to rest, displacement is 0, which means s = 0
So, 0 = 3t^2 - 18t
18t = 3t^2 ( This equation has 1 solution as 0 also, so at t = 0 also, the particle is at rest )
18 = 3t
t = 6
I hope this helps you, Please Mark it the brainliest
MathIsEpic:
Hey, which grade are you studying in?
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