Question

the equation of projectile is y = 16x - x²/4 the horizontal range is-----------(formula= x tan-1/2gx²/u²cos² theta​

Answer 1

Answer:

64

Step-by-step explanation:

put the value of y=0 in the equation and find the roots because the y coordinates at the last point of projectile is 0 and the corresponding value of x is the range

Answer 2

Step-by-step explanation:

Please find the attachment and hope it helps u.