Question

. The equation of SHM with amplitude 4m
and time period 2s with initial phase 1/3
is
1) y=4sin (2nt +1 (3)m
*) y=4sin (ret +T/3)m
3) y=4sin (4t+1/3)
4)y=4 sin(att + T ​

Answer 1

Answer:

The equation of SHM with amplitude 4m and time period 2s with initial phase 1/3 is 3) y=4sin (4t+1/3)