Question

The equation of Tangent to the curve y = x^2 + 1 at (1,1) is

Answer 1

Answer:

y-2x-1 = 0

Step-by-step explanation:

The equation is $y= x^{2} + 1$

Differentiating with respect to x:

dy/dx  =  2x

(We know dy/dx is also called the slope)

Thus as (1,1) , x= 1 so the slope becomes '2'

Using Point-Slope form to make the equation;

$y-y1 = m(x-x1)\\y-1 = 2(x-1)\\y-1 = 2x - 2\\y - 2x = -1\\or \\ y - 2x + 1 = 0$

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