The equation of the circle which touches x-axis and whose centre is (1, 2) is
a) x2 +y2 −2x+4y+1=0 b) x2 +y2 −2x−4y+1=0
c) x2 +y2 +2x+4y+1=0 d) x2 +y2 +4x+2y+4=0
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Answer:
Option B
Step-by-step explanation:
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from above image radius is 2 units
centre is (1,2)
the general equation of circle is (x-h)²+(y-k)²=k²
therefore
(x-1)²+(y-2)²=4
x²+1-2x +y²+4-4y=4
x²+y²-2x-4y+1=0
therefore option B
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