The equation of the lien joining (-2,1,3) and (1,1,4) is
Answers
Answered by
0
Step-by-step explanation:
ANSWER
given Points
A(2,1,3) and B(-4,3,-1)
b
=−4
i
^
+3
j
^
−
k
^
Position vector of line
A=
a
=2
i
^
+
j
^
+3
k
^
normal vector can be calculated by
b
−
a
=
n
=−4
i
^
+3
j
^
−
k
^
−(2
i
^
+
j
^
+3
k
^
)
n
=−4
i
^
+3
j
^
−
k
^
−2
i
^
−
j
^
−3
k
^
n
=−6
i
^
+2
j
^
−4
k
^
eq of line
r
=
a
+λ
n
r
=2
i
^
+
j
^
+3
k
^
+λ(−6
i
^
+2
j
^
−4
k
^
)
r
=2
i
^
+
j
^
+3
k
^
−6λ
i
^
+2λ
j
^
−4λ
k
^
r
=(2−6λ)
i
^
+(1+2λ)
j
^
+(3−4λ)
k
^
r
=2(1−3λ)
i
^
+(1+2λ)
j
^
+(3−4λ)
k
^
Answered By
Similar questions