Question

The equation of the line passing through the point of intersection of the lines
x+y-5=0, 2x-y+4=0 and having intercepts numerically equal is

Answer 1

Answer:

x+y=15

Step-by-step explanation:

x+y-5=0............(1)

2x-y+4=0.........(2)

Adding we get

3x-1=0, x=1/3

from (1)

1/3+y=5

y=15/3-1/3=14/3

Thos the point of intersection is (1/3,14/3)

The equation of the line with numerical equal intecept)say =a) with axes

x/a+y/a=1

x+y=a....................(3)

This line passes through (1/3,14/3)

So 1/3+14/3=a

a=(1+14)/3=15/3=5

Thus the equatio(3) becomes

x+y=15

Answer 2

Step-by-step explanation:

The equation of the line passing through the point of intersection of the lines

x+y-5=0, 2x-y+4=0 and having intercepts numerically equal is