The equation of the line passing through the point of intersection of the lines
x+y-5=0, 2x-y+4=0 and having intercepts numerically equal is
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Answer:
x+y=15
Step-by-step explanation:
x+y-5=0............(1)
2x-y+4=0.........(2)
Adding we get
3x-1=0, x=1/3
from (1)
1/3+y=5
y=15/3-1/3=14/3
Thos the point of intersection is (1/3,14/3)
The equation of the line with numerical equal intecept)say =a) with axes
x/a+y/a=1
x+y=a....................(3)
This line passes through (1/3,14/3)
So 1/3+14/3=a
a=(1+14)/3=15/3=5
Thus the equatio(3) becomes
x+y=15
Answered by
0
Step-by-step explanation:
The equation of the line passing through the point of intersection of the lines
x+y-5=0, 2x-y+4=0 and having intercepts numerically equal is
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