The equation of the line PQ is 3y – 3x + 7 = 0.
(1) Write down the slope of the line PQ,
(11) Calculate the angle that the line PQ makes with the positive direction of x-axis.
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Given: Equation of line
3y-3x+7=0
3y=3x-7
y=(3x-7)/3
y=1x-7/3
Comparing with y=mx+c
where m is the slope of line.
slope = 1
we know that tan45= 1
anglemade by the line with positive direction of x-axis is 45°
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Answer:
write the equation of line PQ
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