Question

the equation of the line whose graph passes through the origin is. ans..a 2x+3y=1. b 2x+3y=0 c 2x+3y=6. d 2x+3y=-4.which one is the right answer​

Answer 1

Option (b). 2x + 3y = 0 is correct

Step-by-step explanation:

Option (a).

The given straight line is

2x + 3y = 1

Satisfying the lhs by origin (0, 0), we get

2 (0) + 3 (0) = 0 + 0 = 0 ≠ 1

∴ the straight line 2x + 3y = 1 does not pass through the origin.

Option (b).

The given straight line is

2x + 3y = 0

Satisfying the lhs by origin (0, 0), we get

2 (0) + 3 (0) = 0 + 0 = 0

∴ the straight line 2x + 3y = 0 passes through the origin.

Option (c).

The given straight line is

2x + 3y = 6

Satisfying the lhs by origin (0, 0), we get

2 (0) + 3 (0) = 0 + 0 = 0 ≠ 6

∴ the straight line 2x + 3y = 6 does not pass through the origin.

Option (d).

The given straight line is

2x + 3y = - 4

Satisfying the lhs by origin (0, 0), we get

2 (0) + 3 (0) = 0 + 0 = 0 ≠ - 4

∴ the straight line 2x + 3y = - 4 does not pass through the origin.

Answer 2

Answer:

option b  is the correct answer

Step-by-step explanation:

let x=0,y=0

2(0)+3(0)=0

0=0

therefore 2x+3y=0 pases through the origin