Math, asked by navvi27, 1 month ago

The equation of the plane passing through the point (1, 2, -3) and perpendicular to the planes 3x + y - 2z = 5 and 2x - 5y - z = 7,
is
(A) 3x - 10y – 2z + 11 = 0
(B) 6x - 5y = 2z = 2 = 0
(C) 11x + y + 172 + 38 = 0
(D) 6x - 5y + 2z + 10 = 0

Answers

Answered by motimarynazareth

Answer:

gujsxjeidiesis8idfjj 8d jud 77

Previous Question

Next Question

Similar questions

Math, 27 days ago

$\displaystyle \int_0^{ \frac{\pi}{2} } cos^5 x\ dx = \:?\:$ Solve the math by " Wallie's theorem " with explanation. Answer : $\frac{8}{15}$ Don't spamming.

Science, 27 days ago

the ___ rests insides the seed until the conditions are right for it to grow,,,,,...

Economy, 27 days ago

question no 9 solve kro jaldi...

Math, 1 month ago

86700000= _________x 10^7...

Physics, 1 month ago

$\sf{What \: is \: a \: Fuse?} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf{What \: are \: the \: functions \: of \: a \: Fuse?}$ ...

Physics, 8 months ago

An artificial satellite is moving in a circular orbit of radio us 36,000km.calculate speed if it take the 24hr to revolve around the earth?

English, 8 months ago

Write 15 sentences on R K NARAYANA LIFE.

English, 8 months ago

answer it plz quickly...

The equation of the plane passing through the point (1, 2, -3) and perpendicular to the planes 3x + y - 2z = 5 and 2x - 5y - z = 7,is(A) 3x - 10y – 2z + 11 = 0(B) 6x - 5y = 2z = 2 = 0(C) 11x + y + 172 + 38 = 0(D) 6x - 5y + 2z + 10 = 0​

Answers

The equation of the plane passing through the point (1, 2, -3) and perpendicular to the planes 3x + y - 2z = 5 and 2x - 5y - z = 7,
is
(A) 3x - 10y – 2z + 11 = 0
(B) 6x - 5y = 2z = 2 = 0
(C) 11x + y + 172 + 38 = 0
(D) 6x - 5y + 2z + 10 = 0