the equation of the straight line cutting off an intercept 8 from x axis and making an angle of 60 degree with the positive direction of y axis is?
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Answers
x + √3y = 8 is the equation of the straight line cutting off an intercept 8 from x axis and making an angle of 60 degree with the positive direction of y axis
Step-by-step explanation:
the equation of the straight line cutting off an intercept 8 from x axis and making an angle of 60 degree with the positive direction of y axis is
Let say equation of line
y = mx + c
Angle of 60° with Y axis
=> 90 + 60° = 150° with x - axis
Slope of line m = Tan150° = - 1/√3
y = -x/√3 + c
the equation of the straight line cutting off an intercept 8 from x axis
=> x = 8 when y =0
=> 0 = -8/√3 + c
=> c = 8/√3
y = -x/√3 + 8/√3
=>√3y = - x + 8
=> x + √3y = 8
x + √3y = 8 is the equation of the straight line cutting off an intercept 8 from x axis and making an angle of 60 degree with the positive direction of y axis
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