Question

The equation of the straight line passing through the point (5, 7) and inclined at 45o to x-axis. If it passes through P whose ordinate is -7 then the abscissa of P is

Answer 1

Answer:

-9

Step-by-step explanation:

Given the point P is P(5,7)

Here slope=tan45=1

Let abscissa=x

so

7-(-7)/5-x=1

14/5-x=1

5-x=14

x=-9