Question

the equation of the tangent to the curve y=secx at the point(0,1) is​

Answer 1

$Given \: equation \: of \: the \: curve :\\y = sec x$

$Slope (m) = \frac{dy}{dx} \\= \frac{d}{dx}(Sec x )\\= Sec x tan x$

$\frac{dy}{dx}_{(0,1)} \\= Sec 0 tan 0 \\= 1 \times 0 \\= 0 \: --(1)$

$\blue{ \therefore Slope (m) = 0 }$

$y - intercept (c) = 1 \: ( given )$

$\red{ Equation \: of \: the \: tangent \: is }$

$\green { y = mx + c }$

$\implies y = 0 \times x + 1$

$\implies y = 1$

Therefore.,

$\red{ Required \: equation \: of \: the \: tangent}$

$\green { y = 1 }$

•••♪

Answer 2

Answer:

ASK YOUR QUESTION

urbansardar52

3 weeks ago

Math

Secondary School

+5 pts

Answered

The equation of the tangent to the curve y=secx at the point(0,1) is​

1

SEE ANSWER

ADD ANSWER

Ask urbansardar52 about this question...

urbansardar52 is waiting for your help.

Add your answer and earn points.

Answer

0

mysticd

Genius

20.4K answers

97.2M people helped

Therefore.,

•••♪

Step-by-step explanation: