Question

The equation of trajectory of projectile is given by
y = x/√3 - gx²/20 , where x and y are in metre.
The maximum range of the projectile is
(a) 8/3 m(b) 4/3 m (c) 3/4 m(d) 3/8 m

Answer 1

Answer:

8 / 3 m

this is answer

Explanation:

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