Physics, asked by khananas7869200, 7 months ago

the equation of transverse wave along a stretched string y=5sinπ÷2(100t-x)in CGS unit the time period of wave is​

Answers

Answered by nirman95
0

Given:

The equation of transverse wave along a stretched string in CGS unit;

 \boxed{y = 5 \sin \bigg \{ \dfrac{\pi}{2} (100t - x)  \bigg \} }

To find:

Time period of wave.

Calculation:

Time period of a progressive transverse wave is the time taken by a specific medium particle to complete 1 full oscillation.

y = 5 \sin \bigg \{ \dfrac{\pi}{2} (100t - x)  \bigg \}

 =  > y = 5 \sin(50\pi t - \dfrac{\pi x}{2})

Comparing the given Equation with a general Equation:

 \boxed{y = a \sin( \omega t - kx) }

 \therefore \:  \omega = 50\pi

Therefore let time period be T ;

 \therefore \: T =  \dfrac{2\pi}{ \omega}

 =  >  \: T =  \dfrac{2\pi}{50\pi}

 =  >  \: T =  \dfrac{2}{50}

 =  >  \: T =  0.04 \: sec

So, final answer is:

 \boxed{ \sf{\: T =  0.04 \: sec}}

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