The equation of two sides of a square are 5x - 12y - 65 = 0 and 5x -12y + 26=0. Find the area of square.
Answers
Answered by
0
Answer:
49 sq. unit.
Explanation:
Prerequisites :
The Distance between parallel lines :
ax+by+c=0,&,ax+by+c'=0 is given by, |c−c'|√a2+b2.
Observe that the given eqns. represent parallellines. So, they
are the eqns. of the opposite lines of the square.
Clearly, the ⊥− distance between them is the length of
a side of a □.
This distance is, |26−(−65)|√52+(−12)2=26+6513=7.
Hence, the reqd. Area of the □ is 72=49 sq. unit.
49 sq. unit.
Explanation:
Prerequisites :
The Distance between parallel lines :
ax+by+c=0,&,ax+by+c'=0 is given by, |c−c'|√a2+b2.
Observe that the given eqns. represent parallellines. So, they
are the eqns. of the opposite lines of the square.
Clearly, the ⊥− distance between them is the length of
a side of a □.
This distance is, |26−(−65)|√52+(−12)2=26+6513=7.
Hence, the reqd. Area of the □ is 72=49 sq. unit.
Similar questions