the equation to the locus of a point which is always equidistant from the points (1,0) and (0,-2) is
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where is the graphic?
Answered by
2
Answer:
2x+4y+3=0
Step-by-step explanation:
A=(1,0) and B=(0,-2)
PA=PB
(x-1)²+y²=x²+(y+2)²
1-2x=4y+4
2x+4y+3=0
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