Question

The equation to the locus of points
equidistant from the points (2,3), (-2,5) is​

Answer 1

Answer:

let the point is (X,O)

as the point is lying on the X axis so it's abcissa is zero.(y=0)

now...

the point (X,0)is equidistant from the points (-2,5);(2,3)

therefore...

therefore the point is (-2,0).