Question

The equation x² + y² + 4x – 2y +1 = 0 is equivalent to
(a) (x + 2)² + (y + 1)²= 6
(b) (x + 2)² + (y + 1)² = 11
(c) (x + 2)² + (y – 1)² = 6
(d) (x + 2)² + (y – 1)² = 11
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Answer 1

Answer:

(c) (x + 2)² + (y – 1)² = 6

x²+4+4x+y²+1_2y=6

x²+y²+4x-2y+5=6

x²+y²+4x-2y+5_6=0

x²+y²+4x-2y+_1=0