The equilibrium A(g) + 4B(g) AB 4(g) is attained by mixing equal moles of A and B in a one litre vessel.
Then at equilibrium
(1) [A] = [B]
(3) [A] < [B]
(4) [AB] > [A]
123/[A] > [B]
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The equillibrium reaction is A(g)+4B(g)⇌AB
4
1 1 − Initial equillibrium
1−x 1−4x x
[A]>[B]....
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