The equilibrium concentration of fluoride ion in a saturated calcium fluoride solution is ______? (show steps)
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Given:
The solubility product (Ksp) of CaF₂ is equal to 3.9*10⁻¹¹
To find:
The concentration of fluoride ion in a saturated solution of CaF₂.
Solution:
- Each mole of CaF₂ produces one moles of Ca²⁺ ions and two moles of F⁻ ions.
- Let s be the solubility of CaF₂.
- The concentration of Ca²⁺ ions will be equal to s and the concentration of F⁻ ions will be equal to 2s.
- Ksp = [Ca²⁺].[F⁻]² = (s).(2s)² = 4s³
- Hence, s = (Ksp/4)^1/3 = 2.13*10⁻⁴ M
- Therefore, concentration of fluoride ions is equal to 2s = 4.26*10⁻⁴ M
Answer:
The concentration of fluoride ion in a saturated solution of CaF₂ is equal to 4.26*10⁻⁴ M
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The equilibrium concentration of fluoride ion in a saturated calcium fluoride solution is ______? (show steps) Get the answers you need, ...
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Given:The solubility product (Ksp) of CaF₂ is equal to 3.9*10⁻¹¹To find:The concentration of fluoride ion in a saturated solution of CaF₂.Solution:Each ... More
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