Chemistry, asked by mridulgarg231, 1 year ago

The equilibrium constant for a reaction A + 2B \rightleftharpoons 2C is 40. The equilibrium constant for reaction C \rightleftharpoons B + \frac{1}{2} A is
(a) 40
(b) \bigg \lgroup \frac{1}{40}\bigg \rgroup ^2
(c) \frac{1}{40}
(d) \frac{1}{(40)^{1/2}}

Answers

Answered by ishucutee
0

Hey friend..

Here is your answer....

B is the right answer

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