Chemistry, asked by aryaparashar5065, 11 months ago

The equilibrium constant for the reaction a(g)+2b(g)→c(g)is 0.25 dm6molâ’2. In a volume of 5 dm3 what amount of a must be mixed with 4 mole of b to yield 1 mole of c at equilibrium?

Answers

Answered by jashansaini614
0

Answer:

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Answered by kiratsingh2435
0

C(g)

[B]

eq

=4mol

K

C

=0.25

K

C

=

[B]

eq

2

[A]

eq

[C]

eq

⇒[A

eq

]=

(

5

4

)

2

×0.25

5

1

[A

eq

]=

28

16

×

100

0.25

5

1

5×16

100

16

20

5

x

=

16

20

x=

16

100

⇒6.25moles

[C]

eq

=1mol

[A]

eq

=?

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