The equilibrium constant for the reaction a(g)+2b(g)→c(g)is 0.25 dm6molâ’2. In a volume of 5 dm3 what amount of a must be mixed with 4 mole of b to yield 1 mole of c at equilibrium?
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C(g)
[B]
eq
=4mol
K
C
=0.25
K
C
=
[B]
eq
2
[A]
eq
[C]
eq
⇒[A
eq
]=
(
5
4
)
2
×0.25
5
1
[A
eq
]=
28
16
×
100
0.25
5
1
⇒
5×16
100
⇒
16
20
5
x
=
16
20
x=
16
100
⇒6.25moles
[C]
eq
=1mol
[A]
eq
=?
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