Chemistry, asked by sanjit319, 9 months ago

The equilibrium constant for the reaction
NH4 NO2)=N2(e) + 2H20() given by​

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Answered by Rohanpawar06
0

Answer:

The rate law for the reaction NH4+ (aq) + NO2- (aq) N2 (g) + 2H2O is given by rate = k [NH4+][NO2-]. At 25 °C, the rate constant is 3.0 x 10-4 M-1 ∙ s-1.

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