Question

The equilibrium constant for the reaction $A_2 \rightleftharpoons 2A$ at 500 K and 700 K are 1 × 10⁻¹⁰ and 1 × 10⁻⁵ respectively. The given reaction is
(a) exothermic
(b) slow
(c) endothermic
(d) fast

Answer 1

Explanation:

(b) For the reaction,

A2

⇌

2A

K=[A]2/[A2]

The value of equilibrium constant is very less and hence, the product concentration is also very less. So, the reaction is slow.