Question

The equilibrium constant K, for the decomposition
of PCI, is 0.625 mole / lit at 300°C. Then the value
of Kc is -
(A) 29.36 atm
(B) 0.0625 atm
(C) 6.25 atm
(D) 0.00625 atm




plz I need solution​

Answer 1

Answer:

PCl5(g) ⇋ PCl3(g) + Cl2(g)

Kp = Kc × (RT)n (R= gas constant, 0.081 L atm mol-1K-1 ; T = 573 K ; n = no. of gaseous molecules of products - no. of gaseous molecules of reactants)

= 0.625 mol L-1 × (0.081 L atm mol-1K-1× 573 K)1

= 29.008