Question

The equilibrium constant K, for the following reaction at 842°C is 7.90 x 10-3. What is K, at
same temperature?
-F2(g) + F(g)
(a) 8.64 x 10-5 (b) 8.26 x 10-4 (c) 7.90 x 10-2 (d) 7.56 x 10-2​

Answer 1

Answer:

D. )

Explanation:

We know Kp=Kc ×(RT)^(∆ng)

∆ng=No. Of moles of products -Reactants

Here ∆ng =1-(1/2)=1/2.

So,Kp = 7.90×10^(-3)×((0.0821×(842+273))^(1/2))

=7.56×10^(-2)

= D)