Question

The equilibrium constant, kp for the reaction, 2nocl(g)2no(g)+cl2(g) is 0.95106 at 298k. The standard gibb's free energy charges, go at 298k will be:

Answer 1

Hey dear,

◆ Answer-
∆G° = 124.31 J

◆ Explaination-
# Given-
T = 298 K
Kp = 0.95106

# Solution-
Reaction occurs as-
2NOCl(g) ---> 2NO(g) + Cl2(g)

Change in no of moles is-
∆n = (2+1) - 2 = 1

Gibb's free energy change is given by-
∆G° = -nRTln(Kp)
∆G° = -1 × 8.314 × 298 × ln(0.95106)
∆G° = 124.31 J

Free energy change is 124.31 J.

Hope this helps...