Question

The equilibrium constant of reaction is 10, what will be the sign of delta g? Will this reaction be spontaneous?

Answer 1

Answer:

sign of Delta g will be positive

Delta g=0. ;Q=K

0=∆G°+RT ln K

∆G°=-RT on K= -2.303log10K

Explanation:

Q is given when the reaction is in progress and yet not reach to equilibrium

the reaction is spontaneous( as it ends at equilibrium)