Question

The equilibrium constant of the reaction CH3COOH (l)+C2H5OH (l)=CH3COOC2H5+H2O is 4.if one mole of each of acetic acid and ethyl alcohol are heated in presence of little concentrated H2SO4 at equilibrium. what amount of ethyl acetate is formed ?

Answer 1

Given: equilibrium constant = 4.

To find: What amount of ethyl acetate is formed ?

Solution:

• We have given that one mole of each of acetic acid and ethyl alcohol are heated in presence of little concentrated H2SO4 at equilibrium.

• The given reaction is:

              CH3COOH (l) + C2H5OH (l) ------------> CH3COOC2H5 + H2O

• Now, in this reaction, we can see that 1 mole of acetic acid is reacting with alcohol. thus by this reaction 1 mole of ethyl acetate is formed.

• So, in equilibrium, 1 mole of ethyl acetate will be formed.

Answer:

               1 mole of ethyl acetate will be formed if one mole of each of acetic acid and ethyl alcohol are heated in presence of little concentrated H2SO4 at equilibrium.

Answer 2

Explanation:

see the above attached photo