Question

The equilibrium constant of the reaction
Cu(s) + 2Ag+ (aq) → Cu2+(aq) + 2Ag(s): Eº=0.46V
at 298 K is
(1) 4.0 x 10^15
(2) 2.4 x 10^10
(3) 2.0 × 10^10
(4) 4.0 × 10^10​

Answer 1

use this formula,

E=E°-0.06/n * logQ

For equilibrium Q will be K and E will be 0 and n=2 ,so> E°=0.06/2logK

calculate by putting the values!

Answer 2

option (1) is the correct answer i. e, 4.0×10^15.

The solution is in the attachment hope it help ✌️