The equivalent mass of iron in the reaction, 3 Fe + 4 H2O Fe2o3 +4h2
(a) 21
(b) 56
c 42
(d) 10
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Fe2 03 is an mixture of FeO and FeO2
In FeO ,Fe has +2 oxidation state
In FeO2,Fe has +4oxiation state
We know that ,
Eq wt=mol .wt/n Factor
In FeO
56/+2=28
In FeO2
56/4=14
Net eq wt=28+14/2=42/2=21
I hope this helps ( ╹▽╹ )
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Answer:
OPTION D
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