Question

the equivalent mass of potassium permanganate in alkaline medium is​

Answer 1

Answer:

As Mn7+ in KMnO4 changes to Mn2+ in acidic medium; it's equivalent weight becomes M/5 (where M is molar mass of KMnO4). Since mass of KMnO4 is 158, equivalent weight in acidic medium is 31.6 grams. In other words, change in oxidation state of KMnO4 in acidic medium is 5. Its' molecular weight is 39+55+64 = 158.

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Answer 2

Here is your answer :

As Mn7+ in KMnO4 changes to Mn2+ in acidic medium;

it's equivalent weight becomes M/5 (where M is molar mass of KMnO4).

Since mass of KMnO4 is 158, equivalent weight in acidic medium is 31.6 grams.

In other words, change in oxidation state of KMnO4 in acidic medium is 5. Its' molecular weight is 39+55+64 = 158.