Question

The equivalent mass of potassium permanganate in alkaline medium is
MnO₄⁻ + 2H2O + 3e⁻ → MnO2 + 4OH⁻
(a) 31.6
(b) 52.7
(c) 79
(d) None of these

Answer 1

equivalent weight of KMnO₄ = Mol. Weight of KMnO₄/ n - factor

In reaction, it is clear that number of electron gained = 3
So, n - factor = 3
Mol.weight of KMnO₄ = 39 + 55 + 4 × 16 = 158 g/mol
Now, equivalent weight = 158/3 = 52.7

Hence, option (b) is correct

Answer 2

Answer:

Explanation:

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