The equivalent of iodine in the reaction 2na2s2o3 + i2 gives lies to 2nai + na2s4o6 is
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Oxidation state of I changes from 0 to −1.
Therefore, change in oxidation state is 1.
Change, per mole of iodine molecule is 1×2 (as we have two atoms of I) = 2.
So, Eq. Wt is =
2
molecular weight
.
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