The equivalent resistance between A and B is
R
A
B
WWW
PR
2R
7
7
AR
3R
4
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THE TOP RESISTOR R AND THE MIDDLE RESISTANCE 2R
ARE IN PARALLEL SO THE NET RESITANCE BETWEEN THEM IS 1/R +1/2R=2R/3.
NOW THE BOTTOM 2 RESISTORS 2R ARE IN SERIES SO THE NET RESISTANCE BETWEEN THEM IS 4R.
NOW 2R/3 AND 4R ARE IN PARALLEL
SO,
3/2R +1/4R=4R/7
THE EQUIVALENT RESISTANCE = 4R/7
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