Question

the equivalent resistance between the point A and B in the following circuit​

Answer 1

starting from the left corner

R1=5+5=10

1/10+1/5=3/10

R2=10/3

R2+5=R3

10/3+5=25/3=R3

1/R3+1/R4=1/R

3/25+1/5

=8/25

=1/R

R=25/8

=3.12

plz mark as brainliest

Answer 2

Given,

A network of resistors is given in the figure.

To Find,

The equivalent resistance between A and B.

Solution,

First, we will find the net resistance of the resistors connected in series

R net = 5+5 = 10 Ω

Now,

The middle resistor and R net  is connected in parallel

1/R' = 1/10+1/5

1/R' = 3/10

R' = 10/3 Ω

Now,

Again R' and lowermost 5 Ω resistor is connected in series

So,

R'' = 10/3+5

R'' = 25/3 Ω

Now,

R'' and the last 5 Ω resistor is connected in parallel

So,

1/R = 1/R''+1/5

1/R = 3/25+1/5

1/R = 8/25

R = 25/8 = 3.12 Ω

Hence, the correct answer is option (a) 3.12 Ω.