Question

the equivalent resistance of the network shown in the figure​

Answer 1

Answer:

n=3

Explanation:

This circuit is in symmetry………

So after applying mirror symmetry in the arm between P and Q, we will find that 3 resisters if 2♎ will lie parallel between P and Q

It's given that equivalent resistance *required* between P and Q is 2/n

So, 1/Req= 1/2+1/2+1/2

= 1/Req= 3/2

=n/2= 3/2

=n=3

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