Question

The equivalent weight of a metal is double than that of oxygen .How many times is the weight of its oxide greater than the weight of metal?

Answer 1

Answer: Weight of the metal oxide is 1.5 times greater than the weight of the metal.

Explanation: As we know,

Equivalent weight of oxygen = 8 g/eq

And we are given that

Equivalent weight of the metal = 2 × Equivalent weight of oxygen

Therefore, equivalent weight of metal = 2 × 8 g/eq = 16 g/eq

Formula for equivalent weight is written as:

$\text{Equivalent weight}=\frac{\text{Atomic mass}}{\text{Valency}}$

$\text{Equivalent weight}=\frac{a}{n}$

$16=\frac{a}{n}$

$a=16n$

Molecular formula of the metal oxide is written as $M_xO_n$

where, x = Valency of oxygen

n = Valency of metal

Mass of metal oxide = 2(16n) + n(16)

Mass of metal = 2(16n)

Ratio of weight of metal oxide and metal is given by:

$\frac{\text{mass of metal oxide}}{\text{Mass of metal}}=\frac{2(16n)+16n}{2(16n)}$

$\text{Mass of metal oxide}=1.5\times \text{Mass of metal}$

Answer 2

Answer:

M/2E=16/E

M=32

MO= 32+16 =48

MO/M=48/32=1.5

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