Question

2y² + 8y - 10 = 0, factoring​

Answer 1

Answer:

2y(y)+8y=10

2y^2+y=10/8

2 y^2+y=5/4

y(2y+1)=5/4

2y+1=5/4(y)

2y+1=5y/4

8y+4=5y

8y-5y= -4

3y= -4

y= -4/3

mark me as brainliest follow and support me friends ❤