Question

The equivalent weight of HCl in the given reaction is:-

K2Cr2O7+14HCl--> 2KCl + 2CrCL3 + 2Cl2+ H2O

Answer 1

answer : 85.1

explanation : we have to find equivalent mass of HCl

reaction is ....

$K_2Cr_2O_7+14HCl\Leftrightarrow 2KCl+2CrCl3+3Cl_2+7H_2O$

HCl is oxidised into Cl2

so, oxidation change from HCl to Cl2 = 1

so, total number of oxidation change = 6

now, equivalent mass of HCl = number of mole of HCl present in reaction × mass of one mole of HCl/total number of change in oxidation

= 14 × (35.5 + 1)/6

= 7 × 36.5/3

= 85.1

hence, answer is 85.1