Question

The equivalent weight of metal whose 1 g carbonate
on heating gives 0.6 g of metal oxide, is
(1) 25 g
(2) 30 g
(3) 35 g
(4) 40g​

Answer 1

Answer:

The answer to the above question is Option A, i.e., 25 g.

It is explained below:

Answer 2

Answer:

The equivalent weight of metal whose 1 g carbonate  on heating gives 0.6 g of metal oxide, is (2) 30 g

Explanation:

Let M be the equivalent weight of the metal  

Equivalent weight of the metal carbonate = Weight of metal + Weight of carbonate  

= Weight of metal + (12 + 3 $\times$ 16)  

= Weight of metal + 60

$\frac {1}{0.6}=\frac {(weight of metal+60)}{(weight of metal+30)}$

we get since the oxidation state of carbonate is 2

1 divided by 0.6 we get 1.67  

$1.67=\frac {(weight of metal+60)}{(weight of metal+30)}$

Cross multiplying (M stands for weight of the metal)

$1.67M+(1.67 \times 30) =M +60\\\\1.67M -1M =60-50\\\\0.67M =10$

So,

$M = \frac {10}{0.67} =15$

Valency of the metal will be 2 since it combines with a carbonate  

Equivalent weight of the metal = 15g times 2 =30g (Answer)