Question

the error in the measurement of diameter of a sphere is 2% what is the percentage error in the measurement of its volume
a) 4%
b) 6%
c) 8%
d) 10%
please reply fast​

Answer 1

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Volume of sphere = 4/3πr^3

given, ∆r/r = 2% = 0.02

so, % error in volume = (3× 0.02) =0.06

= 6%

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Answer 2

Answer:

d=2r

∆d/d=∆r/r=2%

now Volume

$v = \frac{4}{3} \pi \: r {}^{3}$

∆v/v=3(∆r/r)=3×2%=6%