the error in the measurement of the radius of a sphere is 2% .What will be the error in the calculation of its surface area?
[hint:Surface areas=4πr² ,∆A/A= 2∆r/r]
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Answered by
105
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YOUR ANSWER IS ----
Given, error in radius of sphere is 2%
it means ∆r = 2%
now, surface area of sphere is
A = 4πr^2
∆A/A = (2×∆r/r)
∆A/A = 2×2/100 = 0.04
∆A/A×100 = 0.04×100 = 4℅
it means % error in surface area of its measurement is 4%
hope it help you
YOUR ANSWER IS ----
Given, error in radius of sphere is 2%
it means ∆r = 2%
now, surface area of sphere is
A = 4πr^2
∆A/A = (2×∆r/r)
∆A/A = 2×2/100 = 0.04
∆A/A×100 = 0.04×100 = 4℅
it means % error in surface area of its measurement is 4%
hope it help you
Answered by
27
Answer:
4 %
Explanation:
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