The error in the measurement of the radius of a sphere is 2%. What will be the error in the calculation of its volume?
Anonymous:
the answer is 6%
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Answered by
0
the error will be 2/100×rcube........but not sure..:)
Answered by
1
hey there
volume of the sphere=4/3pi*r^3
=r^3=3×2%
=6%
hope it help
{MARK BRAINLIEST}
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