The error in the measurements of mass and volume
of a solid are 5% and 2% respectively. The maximum
percentage error in the measurement of its density
will be :
(a) 10 (b) 25 (c) 7 (d) 3.
(full explanation?)
Answers
Explanation:
First, D= M/V
here , M = 5%
V = 2%
Now according to formula
D×100/100 = M×100/100 + V×100/100
= 5×100/100 + 2×100/100
= 5 + 2
Hope this will help you ..
= 7
Answer:
c) 7
Explanation:
c) 7 Is the correct answer of this question .
Given : The error in the measurements of mass and volume
of a solid are 5 % and 2 % respectively. The maximum
percentage error in the measurement of its density
To solve : The error in the measurements of mass and volume
of a solid are 5 % and 2 % respectively. The maximum
percentage error in the measurement of its density will be :
Solution :
First , D= M / V
here , M = 5 %
V = 2 %
Now according to formula
D × 1 0 0 /1 0 0 = M × 1 0 0 / 1 0 0 + V × 1 0 0 / 1 0 0
= 5 × 1 0 0 /1 0 0 + 2 × 1 0 0 / 1 0 0
= 5 + 2
= 7
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