Question

The error in the measurements of radius of a sphere is 0.4%.The percentage error in its volume is

Answer 1

Answer:

Hey mate your answer is here

That is 1.2%

Mark as brainlist

Answer 2

Concept:

• This question uses relative error calculations
• The relative error is the ratio of the difference between the expected and actual value to the actual value
• when x = a^t,
• relative error Δx/x = t (Δa/a)

Given:

• Error in the measurement of a radius Δr/r = 0.4% = 0.4/100 = 0.004

Find:    

• The percentage error in volume Δv/v

Solution:

• The volume of a sphere V = 4/3πr³
• Therefore, Δv/v = 3 Δr/r
• Δv/v = 3 x 0.004
• Δv/v = 0.012
• In terms of percentage, Δv/v = 0.012 x 100% = 1.2%

Thus, the percentage error in the volume of a sphere is 1.2%

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