The % error in velocity and mass of a particle are 2% and
3% respectively, then % error in kinetic energy will
be___ ?
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Answered by
1
Answer:
%reproduce his own and the lion could be helpful if you could
Answered by
1
Answer:
Explanation:so for finding %error for
K.E=1/2mv^2
ΔK.E=Δm+2ΔV
=2%+6%
=8%
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